Answer:
The dimensions of the largest area are
W = 83.33 ft
L = 125 ft.
Step-by-step explanation:
Let 'x' be the length of the rectangular area
and, 'y' be the width of the rectangular area.
Cost 'C'= 1/2(24x) + 24y + 24x =36x + 24y
To Maximize area
6000= 36x + 24y
y= 250-3x/2
Area'A' = xy= x( 250-3x/2) => 250x - 3/2x²
Taking derivative on both sides and then setting it to zero
A'= 250- 3x =0
x= 250/3 =>83.33ft
->y= 250-3(83.33)/2 =>125ft
A''= -3<0 , verifying by taking second derivative.
Therefore, the dimensions for the plot that would enclose the most area 83.33ft by 125ft