Solve the following system algebraically
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Step-by-step explanation:
I'm going to give you the explanation first.
Let's start by making the equations more manageable.
[tex]y=\frac{x}{2} \\2y=x\\[/tex]
There you are for the first.
Now insert that value into the second:
[tex]2x^{2} -y^2=7\\2(2y)^2-y^2=7\\4y^2-y^2=7\\3y^2=7\\y^2=\frac{7}{3} \\y=+or-\sqrt{\frac{7}{3} }[/tex]
We now have the value for y, and can solve for x.
Can you solve for x on your own?
Feel free to comment with questions. Have a great day!