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equations F= -kx F= m x a or F= m x g g= -9.8 m/s2 When a 0.50 kg-object is attached to a vertically supported spring, it stretches 0.10 m from the equilibrium position. Find k for the spring.

A.
49

B.
-49

C.
.050

D.
-0.05

Respuesta :

Answer:

A. 49

Explanation:

It is always nice to draw a free body diagram to visualize what is going on. (Or that is what my physics teacher told me haha)

Since you are given F=mg, you can substitute your given values (g=-9.8 and m=0.5) to solve for force.

F = -9.8 x 0.5 = -4.9 N

Then substitute -4.9 N and your given displacement (x=0.1) into your given equation to solve for the spring constant (k).

-4.9=-k(0.1) = -4.9/0.1 = -49

-49 = -k, so -49/-1 = 49

k=49

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