(1 point) Suppose that f(x) and g(x) are given by the power series f(x)=6+7x+3x2+5x3+⋯ and g(x)=7+8x+3x2+4x3+⋯. By multiplying power series, find the first few terms of the series for the product h(x)=f(x)⋅g(x)=c0+c1x+c2x2+c3x3+⋯.

Respuesta :

Answer:

f(x).g(x)   =  c0+c1x+c2x2+c3x3+⋯.

[tex]f(x).g(x) = 42 +97x +95x^{2} + 104x^{3} +77x^{4} +27x^{5} + 20x^{6}+....[/tex]

c₀ = 42 , c₁ =97 , c₂ = 95, c₃ =104, ...…...

Step-by-step explanation:

Suppose that f(x) and g(x) are given by the power series

f(x)=6+7x+3x2+5x3+⋯ and

g(x)=7+8x+3x2+4x3+⋯

By multiplying power series ,

f(x).g(x) = (6+7x+3x2+5x3+⋯).(7+8x+3x2+4x3+⋯)

           = 6(7+8x+3x2+4x3+⋯)+7x(7+8x+3x2+4x3+⋯)+3x2(7+8x+3x2+4x3+⋯) + 5x3(7+8x+3x2+4x3+⋯)+......

[tex]f(x).g(x) = 42 +97x +95x^{2} + 104x^{3} +77x^{4} +27x^{5} + 20x^{6}+....[/tex]

f(x).g(x)   =  c0+c1x+c2x2+c3x3+⋯.is the form

[tex]f(x).g(x) = 42 +97x +95x^{2} + 104x^{3} +77x^{4} +27x^{5} + 20x^{6}+....[/tex]

c₀ = 42 , c₁ =97 , c₂ = 95, c₃ =104, ...……

The value of [tex]\rm c_0 = 42[/tex], [tex]\rm c_1 = 97[/tex],  [tex]\rm c_2 = 95[/tex],  [tex]\rm c_3 = 104[/tex] and so on and this can be determined by using the arithmetic operations.

Given :

f(x) and g(x) are given by the power series f(x)=6+7x+3x2+5x3+⋯ and g(x)=7+8x+3x2+4x3+⋯.

Given that f(x) = 6+7x+3[tex]\rm x^2[/tex]+5[tex]\rm x^3[/tex]+⋯ and g(x) = 7+8x+3[tex]\rm x^2[/tex]+4[tex]\rm x^3[/tex]+⋯. So, the following calculation can be used in order to multiply the power series.

[tex]\rm f(x)\times g(x) = (6+7x+3x^2+5x^2+..)\times (7+8x+3x^2+4x^3+..)[/tex]

                 [tex]\rm f(x)\times g(x)=6(7+8x+3x^2+4x^3)+7x(7+8x+3x^2+4x^3)+3x^2(7+8x+3x^2+4x^3)+5x3(7+8x+3x^2+4x^3)+...[/tex]

[tex]\rm f(x) \times g(x) = 42+97x+95x^2+104x^3+77x^4+27x^5+20x^6+...[/tex]    --- (1)

Now, the generalized power series is given by the equation:

[tex]\rm h(x) = f(x) \times g(x) = c_0+c_1x+c_2x^2+c_3x^3+c_4x^4+c_5x^5+c_6x^6+...[/tex]    ---- (2)

Now comparing equation (1) and equation (2).

[tex]\rm c_0 = 42[/tex]

[tex]\rm c_1 = 97[/tex]

[tex]\rm c_2 = 95[/tex]

[tex]\rm c_3 = 104[/tex] and so on.

For more information, refer to the link given below:

https://brainly.com/question/13101306