Answer:
see below
Step-by-step explanation:
exponent to log: [tex]a^b[/tex] = c ---> logₐc = b
ie. question 6
log ₁₀(3x+1) = 2 -----> [tex]10^{2} = 3x+1[/tex]
that will get you through questions 1 to 3, 5 to 6, and 8
in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3
for questions 7 and 9,
remember that:
logₐc + logₐd = logₐ(cd)
logₐc - logₐd = logₐ([tex]\frac{c}{d}[/tex])
remember change of base is [tex]log_{a} b = \frac{log_xb}{log_xa}[/tex], this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e
