For a cube pyramid with a base equal to H^2 and height H, the volume is one-third of a cube with sidelength H.
How to get the area of a pyramid cube?
If the base of the pyramid cube is B, and the height is H, the volume will be:
V = (1/3)*B*H
Notice that if the base has the same dimensions as the height, then we will have that:
B = H^2
In this case, the volume will be:
V = (1/3)*H^2*H = (1/3)*H^3
Then we can see that the volume of this pyramid is one-third of the volume of a cube with similar dimensions.
If you want to learn more about volumes, you can read:
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