Respuesta :
Answer: The amount of hydrogen gas produced in the reaction is 1.04 moles
Explanation:
We are given:
Moles of Mg = 2.08 moles
Moles of HCl = 2.08 moles
The chemical equation for the reaction of magnesium and HCl follows:
[tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]
By Stoichiometry of the reaction:
2 moles of HCl reacts with 1 mole of magnesium metal.
So, 2.08 moles of HCl will react with = [tex]\frac{1}{2}\times 2.08=1.04mol[/tex] of magnesium metal.
As, given amount of magnesium metal is more than the required amount. So, it is considered as an excess reagent.
Thus, HCl is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of HCl produces 1 mole of hydrogen gas
So, 2.08 moles of HCl will produce = [tex]\frac{1}{2}\times 2.08=1.04moles[/tex] of hydrogen gas
Hence, the amount of hydrogen gas produced in the reaction is 1.04 moles
