50 points to whoever gets it correct
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Given
The measure of the arc AC is [tex]m \widehat{A C}=82^{\circ}[/tex]
The measure of the angle ABC is [tex]m \widehat{A BC}=x[/tex]
We need to determine the value of x.
Value of x:
The inscribed angle theorem states that, "the measure of an inscribed angle is half the measure of the intercepted arc".
Applying this theorem, we have;
[tex]m \angle A B C=\frac{1}{2} m \widehat{A C}[/tex]
Substituting the values, we get;
[tex]x=\frac{1}{2}(82^{\circ})[/tex]
[tex]x=41^{\circ}[/tex]
Thus, the value of x is 41°
Therefore, the measure of angle ABC is 41°
Answer:
Here AC = 82⁰
The angle ABC will be half the length of arc AC .
Thus angle ABC = 1/2 × 82 = 41 ⁰