Answer:
The value of dissociation constant of an acid [tex]5.0\times 10^{5}[/tex].
Explanation:
The [tex]pK_a[/tex] of an acid = -5.7
The dissociation constant of the reaction = [tex]K_a[/tex]
The relation between [tex]pK_a[/tex] and [tex] K_a[/tex] is given by ;
[tex]pK_a=-\log[K_a][/tex]
[tex]-5.7=-\log[K_a][/tex]
[tex]K_a=10^{-(-5.7)}=5.012\times 10^{5}\approx 5.0\times 10^{5}[/tex]
The value of dissociation constant of an acid [tex]5.0\times 10^{5}[/tex].
