Answer:
Explanation:
S/N  Age range    Adult Population    Population Internet Users
A Â Â Â 18 Â - Â Â 29 Â Â Â Â Â Â Â Â 478 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 454
B Â Â Â 30 Â - Â Â 49 Â Â Â Â Â Â Â Â 833 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 741
C    50 and above     1644                 1058
       Total           2955                2253
a) Let E = Estimate proportion and A = Internet users
Hence, n(E) = 478 and n(A) = 454
∴ Probability of Internet users (18 - 29), P(A) = n(A)/n(E) = 454/478 = 0.9498 (94.98%)
b) n(E) = 833 and n(B) = 741
∴ Probability of Internet users (30 - 49), P(B) = n(A)/n(E) = 741/833 = 0.8896 (88.96%)
c) n(E) = 1644 and n(C) = 1058
∴ Probability of Internet users (50 and above), P(C) = n(C)/n(E) = 1058/1644 = 0.6436 (64.36%)
d) Let Et = Total estimate proportion
Hence, n(Et) = 2955 and n(A) = 454
∴ Probability of 18 - 29 age range using Internet overall Pt(A) = n(A)/n(Et) = 454/2955 = 0.1536 (15.36%)