ΔABC and ΔDEF are similar by AAA similarity.
Solution:
Sum of the interior angles = 180°
In triangle ABC,
60° + 60° + m∠C = 180°
120° +m∠C = 180°
Subtract 120° from both sides, we get
m∠C = 60°
In triangle DEF,
60° + 60° + m∠F = 180°
120° +m∠F = 180°
Subtract 120° from both sides, we get
m∠F = 60°
Consider ΔABC and ΔDEF,
∠A ≅ ∠D
∠B ≅ ∠E
∠C ≅ ∠F
Therefore by AAA similarity ΔABC ≅ ΔDEF.
ΔABC and ΔDEF are similar triangles.
