84 grams of N2 will be produced in this reaction.
Explanation:
Molecular weight of N2H4 = 14×2 + 4 = 32
Molecular weight of N2O4 = 14×2 + 16×4
= 28 + 64
= 92
moles of N2O4 = 92 / 92 = 1.0
moles of N2H4 = 96 / 32 = 3.0
N2O4 is the limiting reactant (1.0 moles) so 3 moles of N2 will be produced.
14×2×3 = 84 grams.
