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Four couples have reserved seats in a row for a concert. In how many different ways can they be seated if
(a) there are no seating restrictions?
(b) the two members of each couple wish to sit together?

Respuesta :

Answer:

a) 40320 ways

b) 384 ways

Step-by-step explanation:

a) if there are no seating restrictions, the number of ways the 4 couples can be seated is the permutation of 8 persons in 8 seats then

number of ways= permutation of 8 persons in 8 seats = 8! = 40320

b) if each couple will sit together then the number of ways is:

number of ways= number of permutation of 4 integrants of each couple in 4 pairs of seats * number of permutation for a couple in a pair of seats^ number of pair of seats  =    4!  * 2^4  = 384

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