Answer:
yáµ¢ = h
vᵢᵧ = 0
Explanation:
Let initial velocity = u
   final velocity = v
   height = h
   acceleration due to gravity = g
Therefore fro equation of motion,
[tex]v^{2}=u^{2}+2gh[/tex]
Here initial velocity is zero.
Hence, [tex]v^{2}=2gh[/tex]
[tex]v = \sqrt{2gh}[/tex]
but since it points downward and you positive is taken in the up direction
[tex]v = -\sqrt{2gh}[/tex]