Answer:
The area of the larger square is 20 [tex]cm^2[/tex]
Step-by-step explanation:
Given:
The area of the smaller square = [tex]10 cm^2[/tex]
To Find:
The are of the larger square = ?
Solution:
The diagonal of the smaller square = diameter of the circle = sides of the larger square
The diagonal of the smaller square is
=>[tex]\sqrt{2(10)}[/tex]
=>[tex]\sqrt{20}[/tex]
=>[tex]\sqrt{2\times 2 \times 5}[/tex]
=>[tex]2\sqrt{5}[/tex]
Now this diagonal is equal to the side of the larger square
so the are of the larger square is
=>[tex](2\sqrt{5})^2[/tex]
=>[tex](2\sqrt{5}) \times (2\sqrt{5}) [/tex]
=> 20 [tex]cm^2[/tex]
