Answer
given,
frequency of sound (f)= 120 Hz
speed of sound (v)= 343 m/s
a) speed of approaching = 3 % of speed of sound
             = 0.03 x 343 = 10.3 m/s
   frequency you would hear
   [tex]f' = f\dfrac{v+v_0}{v}[/tex]
   [tex]f' = 120 \times \dfrac{343+10.3}{343}[/tex]
      f' = 123.60 Hz
b) Â speed of going away = 3 % of speed of sound
             = 0.03 x 343 = 10.3 m/s
   frequency you would hear
   [tex]f' = f\dfrac{v-v_0}{v}[/tex]
   [tex]f' = 120 \times \dfrac{343-10.3}{343}[/tex]
      f' = 116.39 Hz