contestada

The escape velocity at the surface of Earth is approximately 11 km/s. What is the mass, in units of ME (the mass of the Earth), of a planet with three times the radius of Earth for which the escape speed is three times that for Earth?

Respuesta :

Answer:11 km/s

Explanation:

Given

Escape velocity at the surface of earth is 11 km/s

Escape velocity is given by

[tex]V_e=\sqrt{\frac{2GM}{R}}[/tex]

Escape velocity at the surface of earth

[tex]11=\sqrt{\frac{2GM}{R}}[/tex]--------------------1

If Escape velocity is three times and the radius is also the three times

[tex]V_e_2=\sqrt{\frac{2G(3M)}{3R}}[/tex]

[tex]V_e_2=\sqrt{\frac{2GM}{R}}=V_e[/tex]

i.e. [tex]V_e_2=11 km/s[/tex]