Respuesta :
Answer:
[tex] {x}^{2} - 6x = 7 \\ {x}^{2} - 6x - 7 = 0 \\ {x}^{2} + x - 7x - 7 = 0 \\ x(x + 1) - 7(x + 1) = 0 \\ (x + 1)(x - 7) = 0 \\ \boxed{x = - 1} \\ \boxed{ x = 7}[/tex]
Answer:
[tex] {x}^{2} - 6x = 7 \\ {x}^{2} - 6x - 7 = 0 \\ {x}^{2} + x - 7x - 7 = 0 \\ x(x + 1) - 7(x + 1) = 0 \\ (x + 1)(x - 7) = 0 \\ \boxed{x = - 1} \\ \boxed{ x = 7}[/tex]