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SlowZasob
JA / JC = AB / BC because, as we can see in the picture above, it's the same proportion. So the answer is the fourth one - BC.

I hope that's what you meant and if so that it will help you :)

Answer:

Given: AC, DF, and GI are parallel.

Solution:

In ΔJAB and ΔJDE

∠J is common.

∠JAB=∠JDE→→As, AB║DE, so corresponding angles are equal.

ΔJAB ~ ΔJDE→→[AA similarity]

Similarly, we can prove that,  ΔJ C B and ΔJ FE by AA similarity.

As, we know when triangles are similar their sides are proportional.

[tex]\frac{JA}{JD}=\frac{JB}{JE}=\frac{AB}{DE}\\\\ \frac{JB}{JE}=\frac{JC}{JF}=\frac{BC}{EF}[/tex]

[tex]\frac{JA}{AB}=\frac{1}{JE}\\\\\frac{JC}{BC}=\frac{1}{JE}\\\\\frac{JA}{AB}=\frac{JC}{BC}\\\\= \frac{JA}{JC}=\frac{AB}{BC}[/tex]

Option 4: BC is correct choice.

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