The first car consumed 20 gallons and the second car consumed
40 gallons
Step-by-step explanation:
The information in the problem:
We need to find how many gallons were consumed by each car in
that week
Assume that the first car used x gallons and the second car used
y gallons
∵ The 1st car used x gallons in that week
∵ The 2nd car used y gallons in that week
∵ The total number of gallons were consumed in that week = 60
∴ x + y = 60 ⇒ (1)
∵ The two cars went together 1600 miles
∵ The fuel efficiency of the first car is 40 miles per gallon
∵ The fuel efficiency of the second car is 20 miles per gallon
∵ Distance = fuel efficiency × number of gallons
∴ 40x + 20y = 1600 ⇒ (2)
Let us solve the system of equations to find x and y
Multiply equation (1) by -20 to eliminate y
∵ (-20)x + (-20)y = (-20)(60)
∴ -20x - 20y = -1200 ⇒ (3)
Add equations (2) and (3)
∴ 20x = 400
- Divide both sides by 20
∴ x = 20
Substitute the value of x in equation (1) to find y
∵ 20 + y = 60
- Subtract 20 from both sides
∴ y = 40
The first car consumed 20 gallons and the second car consumed
40 gallons
Learn more:
You can learn more about the system of linear equation in
brainly.com/question/13168205
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