A batter hits the a baseball so that it leaves the bat with an initial speed 37mps at an angle of 53degree find the position of ball after 2 second

Respuesta :

Cos 53 degrees = adj/hyp
Cos 53 degrees = Vx/37mps
37 cos 53 degrees = Vx
Vx = 22.2 mps
sin 53 degrees = opp/hyp
sin 53 degrees = Vy/37 mps
37 mps sin 53 degrees = Vy
Vy = 29.54 mps
So, then
We are missing the altitude I believe

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