(2x^2-3x+1)(x^2-4x-3)
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Answer:
B
Step-by-step explanation:
Given
(2x² - 3x + 1)(x² - 4x - 3)
Each term in the second factor is multiplied by each term in the first factor, that is
2x²(x² - 4x - 3) - 3x(x² - 4x - 3) + 1(x² - 4x - 3) ← distribute parenthesis
= 2[tex]x^{4}[/tex] - 8x³ - 6x² - 3x³ + 12x² + 9x + x² - 4x - 3 ← collect like terms
= 2[tex]x^{4}[/tex] - 11x³ + 7x² + 5x - 3 → B