Respuesta :

altavistard

Answer:

r = +2√3

Step-by-step explanation:

The equation of a circle with center at (0, 0) and radius r is

x^2 + y^2 = r^2.

Here we have

x^2 + y^2 = 12,

and so we can deduce that r^2 = 12.  Then r = +2√3.

luisejr77

Answer:

The radius is: [tex]2\sqrt{3}[/tex]

Step-by-step explanation:

The equation of a circle in center-radius form is:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

Where the center is at the point (h, k) and the radius is "r".

So, given the equation of the circle:

[tex]x^2+y^2=12[/tex]

You can identify that:

[tex]r^2=12[/tex]

Then, solving for "r", you get that the radius of this circle is:

[tex]r=\sqrt{12}\\\\r=2\sqrt{3}[/tex]