If PA = 6, PD = 4 and BE = 5. Find PE
A) 4
B) 5
C) 6
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Answer:
Option A) 4
Step-by-step explanation:
we know that
Applying the Intersecting Secant-Tangent Theorem
[tex]PA^{2}=(BE+PE)( PE)[/tex]
substitute the given values
[tex]6^{2}=(5+PE)( PE)\\ \\36=PE^{2}+5PE\\ \\PE^{2}+5PE-36=0[/tex]
Solve the quadratic equation by graphing
The solution is PE=4 units
see the attached figure