Use the net as an aid to compute the surface area (rounded to the nearest integer) ofvthe triangular pyramid with an equilateral triangle base. A) 106 ft^2 B) 114ft ^2 C) 122ft^2 D) 130ft^2
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Answer:
A) 106 ft^2
Step-by-step explanation:
The total surface area is the area of the base triangular face and the three lateral faces.
The base triangular face has length of its base to be b=6 ft.
The height of this triangle is 5.2 ft.
The area of this triangle is
[tex]Area=\frac{1}{2}\base \times height[/tex]
[tex]Area=\frac{1}{2}\times 6\times 5.2[/tex]
[tex]Area=15.6ft^2=16ft^2[/tex] to the nearest integer
The area of the three lateral face is
[tex]Area=3\times \frac{1}{2}\times 6\times 10=90ft^2[/tex]
The total surface area is therefore 90+16=106 square feet
Answer:
106 ft²
Step-by-step explanation:
The surface area of a triangular pyramid is calculated with the following formula:
[tex]SA = \frac{H B}{2} + \frac{3 B S}{2}[/tex]
Where:
H is the height of the triangle base,
B is the side of the base triangle
S is the length of the slant.
so, if we plug in our numbers, we have:
[tex]SA = \frac{5.2 * 6}{2} + \frac{3 * 6 * 10}{2} = 15.6 + 90 = 105.6[/tex]
105.6 sq ft, which we round up to 106 square feet.