Help me find the lateral and the surface area I have to round to the nearest tenths if necessary
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Answer:
Step-by-step explanation:
We have four congruent triangles with base b = 16cm and height h = 12cm.
The formula of an area of a triangle:
[tex]A=\dfrac{bh}{2}[/tex]
Substitute:
[tex]A=\dfrac{(16)(12)}{2}=(8)(12)=96\ cm^2[/tex]
The latearal area:
[tex]L.A.=4A\to L.A.=4(96)=384\ cm^2[/tex]
For the surface area we need the area of a base.
The base is a square with side a = 16cm.
The area of the base:
[tex]B=16^2=256\ cm^2[/tex]
The surface area:
[tex]S.A.=L.A.+B\to S.A.=384+256=640\ cm^2[/tex]