Please help!
f(x)= 3x/ x^2-16
a) x= -16
b) x= -4
c) x= 0
d) x= 4
e) x= 16
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Answer:
x = 1 and x = 2
x = 4 and x = -4
Step-by-step explanation:
Vertical asymptotes appear where the function does not have a value. This is most commonly when the denominator of a rational function is 0. Find the asymptotes by factoring the denominator and setting it equal to 0. Then solve for x.
First equation
x² - 3x + 2 factors into (x-1)(x-2)
When x-1 = 0, x = 1. When x-2=0, x = 2. The V.A. are at x = 1 and x = 2.
Second equation
x² - 16 factors into (x+4)(x-4)
When x+4= 0, x = -4. When x-4 = 0, then x = 4. The V.A. are at x = -4 and x = 4.