The polygons are similar, but not necessarily drawn to scale. Find the value of x.
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If the shapes are similar, the correspondent sides are in proportion:
[tex]AB\div DE = BC \div EF[/tex]
Let's plug the values and solve for x:
[tex]5x \div 5 = 4 \div x \iff \dfrac{5x}{5}=\dfrac{4}{x}\iff x = \dfrac{4}{x}[/tex]
Multiply both sides by x to get
[tex]x^2=4 \iff x=\pm2[/tex]
The only feasible solution, though, is [tex]x=2[/tex], because it wouldn't make sense to have negative lengths.
The value of x in the similar polygons in the given diagram is: B. x = 2.
Similar polygons have the same shape but different size, thus, the length of their corresponding sides are proportional together and have equal ratio.
In essence, we will have the following ratio:
5x/5 = 4/x
(x)(5x) = (4)(5)
5x² = 20
5x²/5 = 20/5
x² = 4
x = √4
x = 2 (option B)
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