Answer:
d. [tex]x=-1,2,\:or\:5[/tex]
Step-by-step explanation:
The given equation is;
[tex]x^3-6x^2+3x+10=0[/tex]
To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator.
The corresponding function is
[tex]f(x)=x^3-6x^2+3x+10[/tex]
The solution to [tex]x^3-6x^2+3x+10=0[/tex] is where the graph touches the x-axis.
We can see from the graph that; the x-intercepts are;
(-1,0),(2,0) and (5,0).
Therefore the real solutions are:
[tex]x=-1,2,\:or\:5[/tex]
