Let f(x)=6/−2+2e^−0.3x . What is f(−4) ?

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ANSWER: 1.3

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calculista calculista · Answer 1 · 2019-04-12T17:32:07+02:00

Answer:

[tex]f(-4)=1.3[/tex]

Step-by-step explanation:

we have

[tex]f(x)=\frac{6}{-2+2e^{-0.3x}}[/tex]

we know that

f(-4) is the value of the function for x=-4

substitute x=-4 in the function

[tex]f(-4)=\frac{6}{-2+2e^{-0.3(-4)}}[/tex]

[tex]f(-4)=\frac{6}{-2+2e^{1.2}}[/tex]

[tex]f(-4)=1.3[/tex]

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EamonnAdams1992 EamonnAdams1992 · Answer 2 · 2019-08-19T09:30:01+02:00

Answer:

1.94

Step-by-step explanation:

We substitute -4 into as x in the equation, but first what is e?

e is a term that represents the base of a natural logarithm and is a irrational number, its called Euler's number. e is equivalent to:

[tex]e=2.718[/tex]

We can substitute -4 into the equation

[tex]=6/(-2+2*(2.718^(-0.3*-4)))[/tex]

[tex]=6/(-2+2*(2.718^(1.2)))[/tex]

[tex]=6/(-2+2*2.54)[/tex]

[tex]=6/(3.09)[/tex]

[tex]=1.94

Therefore f(-4)=1.94