Evaluate the logarithm in e^2 (Picture provided)
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Answer: option d
Step-by-step explanation:
By definition, you know that:
[tex]log_a(a^n)=n[/tex]
Where: a is the base of the logarithm.
You also know that the base of [tex]ln[/tex] is the Euler's number, which is "[tex]e[/tex]".
Therefore, when you apply the property shown above, you obtain the following:
[tex]ln(e^2)=log_e(e^2)\\ln(e^2)=2[/tex]
Then, you can conclude that the answer is the shown in the option d.