In the following image, AB is parallel to DC, and BC is a transversal intersecting both parallel lines. The measure of angle ABC is 118°

Answer:
n° = 62°
p° = 62°
q° = 118°
v° = 84°
w° = 138°
Step-by-step explanation:
angle ABC is 118°
so
m° + 118° = 180
m° = 180° - 118°
m° = 62°
n° = m° = 62° (corresponding angles are equal since AB is parallel to DC, and BC)
p° = n° = 62° (vertical angles are equal)
q° + n° = 180° (linear pair angles)
q° + 62° = 180°
q° = 180° - 62°
q° = 118°
v° + 96° = 180° (linear pair angles)
v° = 180° - 96°
v° = 84°
w° + 42° = 180 (linear pair angles)
w° = 180° - 42°
w° = 138°
Answer:
n° = 62°
p° = 62°
q° = 118°
v° = 84°
w° = 138°
Step-by-step explanation:
angle ABC is 118°
so
m° + 118° = 180
m° = 180° - 118°
m° = 62°
n° = m° = 62° (corresponding angles are equal since AB is parallel to DC, and BC)
p° = n° = 62° (vertical angles are equal)
q° + n° = 180° (linear pair angles)
q° + 62° = 180°
q° = 180° - 62°
q° = 118°
v° + 96° = 180° (linear pair angles)
v° = 180° - 96°
v° = 84°
w° + 42° = 180 (linear pair angles)
w° = 180° - 42°
w° = 138°