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How can this system be brought to equilibrium?

A) Add a 5 N force acting in the same direction as the 10 N force.

B) Add a 10 N force acting in the same direction as the 10 N force.

C) Add a 10 N force acting in the same direction as the 20 N force.

D) Add a 20 N force acting in the same direction as the 20 N force.


A car's position in relation to time is plotted on the graph. What is the car's average velocity?

A) 5 m/s

B) 10 m/s

C) 30 m/s

D) 50 m/s

How can this system be brought to equilibriumA Add a 5 N force acting in the same direction as the 10 N force B Add a 10 N force acting in the same direction as class=
How can this system be brought to equilibriumA Add a 5 N force acting in the same direction as the 10 N force B Add a 10 N force acting in the same direction as class=

Respuesta :

tootooroo
Hello! The answer is B and B.

When a system is in equilibrium, this means that the net force/total force = 0N. Hence you need to add 10N to the 10N force acting towards the right so that the 20N acting in opposite directions will ‘cancel’ out to get a net force of 0N.

Average velocity is calculated by distance travelled divided by time. Hence, velocity = 50m/5s = 10ms^1
LITTYLITZY

Answer:

To make the opposing forces equal, add a 10 N force acting in the same direction as the 10 N force. The forces opposing each other will be 20 Newtons, equal and opposite.

Explanation:

To make the opposing forces equal, add a 10 N force acting in the same direction as the 10 N force. The forces opposing each other will be 20 Newtons, equal and opposite.

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