Find the sixth term of the following geometric sequence.
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Answer:
[tex]a_{6}[/tex] = - [tex]\frac{7}{16}[/tex]
Step-by-step explanation:
The n th term of a geometric sequence is
[tex]a_{n}[/tex] = a[tex]r^{n-1}[/tex]
where a is the first term and r the common ratio
here a = 14 and r = [tex]\frac{-7}{14}[/tex] = - [tex]\frac{1}{2}[/tex], hence
[tex]a_{6}[/tex] = 14 × [tex](-1/2)^{5}[/tex] = 14 × - [tex]\frac{1}{32}[/tex] = - [tex]\frac{7}{16}[/tex]