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tonytlan06

So first let's find ∠BCE: (Assume that the line ABCD is a straight line)

The angle on a line is 180°.

So ∠BCE = 180° - 64° - 90° = 26°

Now, let's find ∠EBC:

∠EBC = 180° - 3x.

The sum of the angles in a triangle is also 180°. So if you add up the angles in the triangle, you should get 180°.

∠BCE + ∠EBC + ∠BEC = 180°

26° + (180° - 3x) + x = 180°

Now, combine like terms:

206° - 2x = 180°

Subtract both sides by 206°.

-2x = -26

Divide both sides by -2 and you'll get:

x = 13°.

sparkledo
B,C x=32
AD 3x =60
showing work :
every to angles are the same but the BC is half of F so
[tex]64 \div 2 = 32[/tex]
since the total angle of a line is 180 you will get an equation so
[tex]3x = 180 \\ x = \frac{180}{3} \\ x = 60[/tex]
that 's it. I hope it right
I love math

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