ƒ(x)=sqrt(8x) and g(x)=1/(x − 4)
which value is in the domain of FoG
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1. Determine what is the rule for function [tex](f\circ g)(x).[/tex]
[tex](f\circ g)(x)=f(g(x))=f\left(\dfrac{1}{x-4}\right)=\sqrt{8\cdot \dfrac{1}{x-4}}=\sqrt{\dfrac{8}{x-4}}.[/tex]
2. The domain of the function [tex](f\circ g)(x)[/tex] - all x that sutisfy:
3. Solve them:
Then you can state that [tex]x>4[/tex] is the domain.
Answer: x>4.