contestada

Two coconuts fall freely from rest at the same time, one from a tree twice as high as the other. If the coconut from the shorter tree takes 2.0 s to reach the ground, how long will it take the other coconut to reach the ground?

Respuesta :

Wee can use here kinematics

as we know that

[tex]y = v*t + \frac{1}{2} at^2[/tex]

for shorter tree we know that

[tex]y = 0 + \frac{1}{2}*9.8 * 2^2[/tex]

[tex]y = 19.6 meter[/tex]

now since we know that other tree is twice high

So height of other tree is y = 39.2 m

now again by above equation

[tex]y = v*t + \frac{1}{2} at^2[/tex]

[tex]39.2 = 0 + \frac{1}{2}*9.8 * t^2[/tex]

[tex]t = 2.83 s[/tex]

so the time taken is 2.83 s

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