Round your answer to the nearest hundredth
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[tex] \bf f(x)=2(x)^2+5\sqrt{(x+2)}\qquad \qquad \stackrel{x=0}{f(0)}=2(0)^2+5\sqrt{(0+2)}
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f(0)=0+5\sqrt{2}\implies f(0)=5\sqrt{2}\implies f(0)\approx 7.07106781186547524
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f(0)\approx \stackrel{rounded~up}{7.07} [/tex]