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konrad509

[tex] 44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\
121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\
\text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4 [/tex]

shubhamchouhanvrVT

The greatest common factor will be equal to 11j²k⁴.

What is the greatest common factor?

The largest factor of the two numbers which divides both the numbers is called as greatest common factor or GCF.

Here we have two numbers

44j⁵k⁴   and   121j²k⁶

We will find the factors of the both the given expressions:-

44 j⁵ k⁴  =  2²  x   11   x   j⁵    x   k⁴

121  j²  k⁶  =  11²   x   j²   x  k⁶

We can see that the highest common factor among the factors are:-

=  11 j² k⁴

Therefore the greatest common factor will be equal to 11j²k⁴.

To know more about GCF follow

https://brainly.com/question/219464

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