Pleaseee help with 22 & 23 !! ASAP !!

#22. We are given that y = 1/4. So, we want to plug this value into the expression 15/y:
15/(1/4)
When you divide by a fraction, you should follow the rule “flip the guy and multiply”. Basically, 15/(1/4) = 15 * 4 = 60.
The answer for #22 is (D).
#23. We can use a proportion:
(The shaded area)/(entire circle area) = (360 - 60)/360
But, we don’t have to find the areas of the region and circle; we can just solve the fraction:
(360 - 60)/360 = 300/360 = 30/36 = 5/6
The answer for #23 is (A).
Hey!
22) If y = [tex] \frac{1}{4} [/tex] then [tex] \frac{15}{y} = 15 \div \frac{1}{4} [/tex]
To divide fractions, you have to keep, change, flip.
[tex] Keep\ \frac{15}{1} \\ Change\ \div to \times \\ Flip \frac{1}{4} = \frac{4}{1} [/tex]
It becomes: [tex] \frac{15}{1} \times \frac{4}{1} = \frac{60}{1} \rightarrow 60 [/tex]
22. D)60
23) Circles measure 360°. 50° is left. Subtract 50 from 360 and make a fraction, using the difference as a numerator, and 360 as the denominator.
[tex] 360 - 60 = 300 [/tex]
The fraction becomes:
[tex] \frac{300 \div 30}{360 \div 30} = \frac{10 \div 2}{12 \div 2} = \frac{5}{6} [/tex]
23) A. [tex] \bf\frac{5}{6} [/tex]
Good luck and hope this helps! :)