Find the equation of the line that had a slope of 5 and passes through (-3,2)

1. None of these
2. y=2x+5
3. y=5x+17
4. 0=5x+17
5. y=2x
6. 17=5x+y

Respuesta :

[tex] \bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\qquad \qquad \qquad
slope = m\implies 5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=5[x-(-3)]\implies y-2=5(x+3)
\\\\\\
y-2=5x+15\implies y=5x+17 [/tex]

the equation is in the form of y- y1 = m (x- x1) so y-2 = 5(x-(-3))

y-2 = 5x +15 so y= 5x +17 ( Adding +2 on both sides)

3 is your choice