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A square steel plate is 10.0 cm on a side and 0.500 cm thick. (a) find the shear strain that results if a force of magnitude 9.0 × 105???? is applied to each of the four sides, parallel to the

Respuesta :

Shear stress on the steel plate is given by

[tex] Stress = \frac{F}{A}[/tex]

[tex] Stress = \frac{9*10^5 }{0.10 * 0.10}[/tex]

[tex] Stress = 9 * 10^7 N/m^2[/tex]

now in order to find shear strain we can use

[tex]strain = \frac{stress}{shear modulus}[/tex]

shear modulus of steel is given by

[tex]\sigma = 78 * 10^9 N/m^2[/tex]

now by above formula we will have

[tex] strain = \frac{9 * 10^7}{78 * 10^9}[/tex]

[tex]strain = 1.15 * 10^{-3}[/tex]

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