we have that
[tex]f(x)=x^{3}[/tex]
we know that
[tex]A(0,0)-------> A'(3,0)[/tex]
the rule of the translation is
[tex](x,y)-----> (x+3,y)[/tex]
that means
the translation is [tex]3[/tex] units to the right
so
the equation of g(x) is
[tex]g(x)=(x-h)^{3}[/tex]
where
[tex]h=3\ units[/tex]
substitute
[tex]g(x)=(x-3)^{3}[/tex]
therefore
the answer is
[tex]g(x)=(x-3)^{3}[/tex]
