Which is the equation of the line passing through (0, 8) and (4, 0)?
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The equation of line that goes through the points (0, 8) and (4, 0) is
y= -1/2 x+4.
The correct option is (A)
The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term.
It is an equation of degree one, with variables x and y. The values of x and y represent the coordinates of the point on the line represented in the coordinate plane.
we have,
x1=0, x2= 8, y1= 4 and y2=0
Now, equation of line
(y-y1)= (y2-y1)/(x2-x1)* (x-x1)
y-4= (0-4)/(8-0)*(x-0)
y-4= -1/2 x
y= -1/2 x+4
Hence, the equation of line is y= -1/2 x+4
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